(2x+1)(x-2)=3x

Solution for (2x+1)(x-2)=3x equation:

(2x+1)(x-2)=3x

We move all terms to the left:

(2x+1)(x-2)-(3x)=0

We add all the numbers together, and all the variables

-3x+(2x+1)(x-2)=0

We multiply parentheses ..

(+2x^2-4x+x-2)-3x=0

We get rid of parentheses

2x^2-4x+x-3x-2=0

We add all the numbers together, and all the variables

2x^2-6x-2=0

a = 2; b = -6; c = -2;
Δ = b2-4ac
Δ = -62-4·2·(-2)
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{13}}{2*2}=\frac{6-2\sqrt{13}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{13}}{2*2}=\frac{6+2\sqrt{13}}{4}
$