(2x+1)(x-3)=(x+3)(2X+5)

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Solution for (2x+1)(x-3)=(x+3)(2X+5) equation: 



(2x+1)(x-3)=(x+3)(2x+5)

We move all terms to the left:

(2x+1)(x-3)-((x+3)(2x+5))=0

We multiply parentheses ..

(+2x^2-6x+x-3)-((x+3)(2x+5))=0



We calculate terms in parentheses: -((x+3)(2x+5)), so:

(x+3)(2x+5)

We multiply parentheses ..

(+2x^2+5x+6x+15)

We get rid of parentheses

2x^2+5x+6x+15

We add all the numbers together, and all the variables

2x^2+11x+15

Back to the equation:

-(2x^2+11x+15)



We get rid of parentheses

2x^2-2x^2-6x+x-11x-3-15=0

We add all the numbers together, and all the variables

-16x-18=0

We move all terms containing x to the left, all other terms to the right

-16x=18

x=18/-16

x=-1+1/8

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