(2x+1)(x-4)+13=2x-10x

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Solution for (2x+1)(x-4)+13=2x-10x equation:



(2x+1)(x-4)+13=2x-10x
We move all terms to the left:
(2x+1)(x-4)+13-(2x-10x)=0
We add all the numbers together, and all the variables
(2x+1)(x-4)-(-8x)+13=0
We get rid of parentheses
(2x+1)(x-4)+8x+13=0
We multiply parentheses ..
(+2x^2-8x+x-4)+8x+13=0
We get rid of parentheses
2x^2-8x+x+8x-4+13=0
We add all the numbers together, and all the variables
2x^2+x+9=0
a = 2; b = 1; c = +9;
Δ = b2-4ac
Δ = 12-4·2·9
Δ = -71
Delta is less than zero, so there is no solution for the equation

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