(2x+1)(x-4)-(3x+6)(2x-8)=(3x+5)(2x-6)-(5x+2)(2x-3)

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Solution for (2x+1)(x-4)-(3x+6)(2x-8)=(3x+5)(2x-6)-(5x+2)(2x-3) equation:



(2x+1)(x-4)-(3x+6)(2x-8)=(3x+5)(2x-6)-(5x+2)(2x-3)
We move all terms to the left:
(2x+1)(x-4)-(3x+6)(2x-8)-((3x+5)(2x-6)-(5x+2)(2x-3))=0
We multiply parentheses ..
(+2x^2-8x+x-4)-(3x+6)(2x-8)-((3x+5)(2x-6)-(5x+2)(2x-3))=0
We calculate terms in parentheses: -((3x+5)(2x-6)-(5x+2)(2x-3)), so:
(3x+5)(2x-6)-(5x+2)(2x-3)
We multiply parentheses ..
(+6x^2-18x+10x-30)-(5x+2)(2x-3)
We get rid of parentheses
6x^2-18x+10x-(5x+2)(2x-3)-30
We multiply parentheses ..
6x^2-(+10x^2-15x+4x-6)-18x+10x-30
We add all the numbers together, and all the variables
6x^2-(+10x^2-15x+4x-6)-8x-30
We get rid of parentheses
6x^2-10x^2+15x-4x-8x+6-30
We add all the numbers together, and all the variables
-4x^2+3x-24
Back to the equation:
-(-4x^2+3x-24)
We get rid of parentheses
2x^2+4x^2-8x+x-3x-(3x+6)(2x-8)-4+24=0
We multiply parentheses ..
2x^2+4x^2-(+6x^2-24x+12x-48)-8x+x-3x-4+24=0
We add all the numbers together, and all the variables
6x^2-(+6x^2-24x+12x-48)-10x+20=0
We get rid of parentheses
6x^2-6x^2+24x-12x-10x+48+20=0
We add all the numbers together, and all the variables
2x+68=0
We move all terms containing x to the left, all other terms to the right
2x=-68
x=-68/2
x=-34

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