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(2x+1)(x+1)=90
We move all terms to the left:
(2x+1)(x+1)-(90)=0
We multiply parentheses ..
(+2x^2+2x+x+1)-90=0
We get rid of parentheses
2x^2+2x+x+1-90=0
We add all the numbers together, and all the variables
2x^2+3x-89=0
a = 2; b = 3; c = -89;
Δ = b2-4ac
Δ = 32-4·2·(-89)
Δ = 721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{721}}{2*2}=\frac{-3-\sqrt{721}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{721}}{2*2}=\frac{-3+\sqrt{721}}{4} $
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