(2x+1)*2=9x-128

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Solution for (2x+1)*2=9x-128 equation: 



(2x+1)*2=9x-128

We move all terms to the left:

(2x+1)*2-(9x-128)=0

We multiply parentheses

4x-(9x-128)+2=0

We get rid of parentheses

4x-9x+128+2=0

We add all the numbers together, and all the variables

-5x+130=0

We move all terms containing x to the left, all other terms to the right

-5x=-130

x=-130/-5

x=+26

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