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(2x+1)*3=5*(1-x)
We move all terms to the left:
(2x+1)*3-(5*(1-x))=0
We add all the numbers together, and all the variables
(2x+1)*3-(5*(-1x+1))=0
We multiply parentheses
6x-(5*(-1x+1))+3=0
We calculate terms in parentheses: -(5*(-1x+1)), so:We get rid of parentheses
5*(-1x+1)
We multiply parentheses
-5x+5
Back to the equation:
-(-5x+5)
6x+5x-5+3=0
We add all the numbers together, and all the variables
11x-2=0
We move all terms containing x to the left, all other terms to the right
11x=2
x=2/11
x=2/11
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