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(2x+1)+(2x+3)+(2x+5)+(2x+7)+(2x+9)/5=71
We move all terms to the left:
(2x+1)+(2x+3)+(2x+5)+(2x+7)+(2x+9)/5-(71)=0
We get rid of parentheses
2x+2x+2x+2x+(2x+9)/5+1+3+5+7-71=0
We multiply all the terms by the denominator
2x*5+2x*5+2x*5+2x*5+(2x+9)+1*5+3*5+5*5+7*5-71*5=0
We add all the numbers together, and all the variables
2x*5+2x*5+2x*5+2x*5+(2x+9)-275=0
Wy multiply elements
10x+10x+10x+10x+(2x+9)-275=0
We get rid of parentheses
10x+10x+10x+10x+2x+9-275=0
We add all the numbers together, and all the variables
42x-266=0
We move all terms containing x to the left, all other terms to the right
42x=266
x=266/42
x=6+1/3
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