(2x+1)+(2x-5)=108

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Solution for (2x+1)+(2x-5)=108 equation:


Simplifying
(2x + 1) + (2x + -5) = 108

Reorder the terms:
(1 + 2x) + (2x + -5) = 108

Remove parenthesis around (1 + 2x)
1 + 2x + (2x + -5) = 108

Reorder the terms:
1 + 2x + (-5 + 2x) = 108

Remove parenthesis around (-5 + 2x)
1 + 2x + -5 + 2x = 108

Reorder the terms:
1 + -5 + 2x + 2x = 108

Combine like terms: 1 + -5 = -4
-4 + 2x + 2x = 108

Combine like terms: 2x + 2x = 4x
-4 + 4x = 108

Solving
-4 + 4x = 108

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 4x = 108 + 4

Combine like terms: -4 + 4 = 0
0 + 4x = 108 + 4
4x = 108 + 4

Combine like terms: 108 + 4 = 112
4x = 112

Divide each side by '4'.
x = 28

Simplifying
x = 28

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