(2x+1)+(4x+3)=(7x-7)

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Solution for (2x+1)+(4x+3)=(7x-7) equation: 



(2x+1)+(4x+3)=(7x-7)

We move all terms to the left:

(2x+1)+(4x+3)-((7x-7))=0

We get rid of parentheses

2x+4x-((7x-7))+1+3=0



We calculate terms in parentheses: -((7x-7)), so:

(7x-7)

We get rid of parentheses

7x-7

Back to the equation:

-(7x-7)



We add all the numbers together, and all the variables

6x-(7x-7)+4=0

We get rid of parentheses

6x-7x+7+4=0

We add all the numbers together, and all the variables

-1x+11=0

We move all terms containing x to the left, all other terms to the right

-x=-11

x=-11/-1

x=+11

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