(2x+1)+6(3x+4)=31

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Solution for (2x+1)+6(3x+4)=31 equation: 



(2x+1)+6(3x+4)=31

We move all terms to the left:

(2x+1)+6(3x+4)-(31)=0

We multiply parentheses

(2x+1)+18x+24-31=0

We get rid of parentheses

2x+18x+1+24-31=0

We add all the numbers together, and all the variables

20x-6=0

We move all terms containing x to the left, all other terms to the right

20x=6

x=6/20

x=3/10

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