(2x+1)-3(8x+2)=27

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Solution for (2x+1)-3(8x+2)=27 equation: 



(2x+1)-3(8x+2)=27

We move all terms to the left:

(2x+1)-3(8x+2)-(27)=0

We multiply parentheses

(2x+1)-24x-6-27=0

We get rid of parentheses

2x-24x+1-6-27=0

We add all the numbers together, and all the variables

-22x-32=0

We move all terms containing x to the left, all other terms to the right

-22x=32

x=32/-22

x=-1+5/11

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