(2x+1)-3(x-2)=x+6

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Solution for (2x+1)-3(x-2)=x+6 equation: 



(2x+1)-3(x-2)=x+6

We move all terms to the left:

(2x+1)-3(x-2)-(x+6)=0

We multiply parentheses

(2x+1)-3x-(x+6)+6=0

We get rid of parentheses

2x-3x-x+1-6+6=0

We add all the numbers together, and all the variables

-2x+1=0

We move all terms containing x to the left, all other terms to the right

-2x=-1

x=-1/-2

x=1/2

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