(2x+1)-3(x-5)=-x+16

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Solution for (2x+1)-3(x-5)=-x+16 equation: 


Simplifying
(2x + 1) + -3(x + -5) = -1x + 16

Reorder the terms:
(1 + 2x) + -3(x + -5) = -1x + 16

Remove parenthesis around (1 + 2x)
1 + 2x + -3(x + -5) = -1x + 16

Reorder the terms:
1 + 2x + -3(-5 + x) = -1x + 16
1 + 2x + (-5 * -3 + x * -3) = -1x + 16
1 + 2x + (15 + -3x) = -1x + 16

Reorder the terms:
1 + 15 + 2x + -3x = -1x + 16

Combine like terms: 1 + 15 = 16
16 + 2x + -3x = -1x + 16

Combine like terms: 2x + -3x = -1x
16 + -1x = -1x + 16

Reorder the terms:
16 + -1x = 16 + -1x

Add '-16' to each side of the equation.
16 + -16 + -1x = 16 + -16 + -1x

Combine like terms: 16 + -16 = 0
0 + -1x = 16 + -16 + -1x
-1x = 16 + -16 + -1x

Combine like terms: 16 + -16 = 0
-1x = 0 + -1x
-1x = -1x

Add 'x' to each side of the equation.
-1x + x = -1x + x

Combine like terms: -1x + x = 0
0 = -1x + x

Combine like terms: -1x + x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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