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(2x+1)/(3x+2)=8
We move all terms to the left:
(2x+1)/(3x+2)-(8)=0
Domain of the equation: (3x+2)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
3x!=-2
x!=-2/3
x!=-2/3
x∈R
(2x+1)-8*(3x+2)=0
We multiply parentheses
(2x+1)-24x-16=0
We get rid of parentheses
2x-24x+1-16=0
We add all the numbers together, and all the variables
-22x-15=0
We move all terms containing x to the left, all other terms to the right
-22x=15
x=15/-22
x=-15/22
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