(2x+1)/(3x+2)=8

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Solution for (2x+1)/(3x+2)=8 equation: 



(2x+1)/(3x+2)=8

We move all terms to the left:

(2x+1)/(3x+2)-(8)=0



Domain of the equation: (3x+2)!=0

We move all terms containing x to the left, all other terms to the right

3x!=-2

x!=-2/3

x!=-2/3

x∈R



We multiply all the terms by the denominator


(2x+1)-8*(3x+2)=0

We multiply parentheses

(2x+1)-24x-16=0

We get rid of parentheses

2x-24x+1-16=0

We add all the numbers together, and all the variables

-22x-15=0

We move all terms containing x to the left, all other terms to the right

-22x=15

x=15/-22

x=-15/22

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