(2x+1)/(3x-2)=1

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Solution for (2x+1)/(3x-2)=1 equation: 


D( x )

3*x-2 = 0

3*x-2 = 0

3*x-2 = 0

3*x-2 = 0 // + 2

3*x = 2 // : 3

x = 2/3

x in (-oo:2/3) U (2/3:+oo)

(2*x+1)/(3*x-2) = 1 // - 1

(2*x+1)/(3*x-2)-1 = 0

(2*x+1)/(3*x-2)+(-1*(3*x-2))/(3*x-2) = 0

2*x-1*(3*x-2)+1 = 0

3-x = 0

(3-x)/(3*x-2) = 0

(3-x)/(3*x-2) = 0 // * 3*x-2

3-x = 0

3-x = 0 // - 3

-x = -3 // * -1

x = 3

x = 3

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