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(2x+1)/(3x-2)=5/4
We move all terms to the left:
(2x+1)/(3x-2)-(5/4)=0
Domain of the equation: (3x-2)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
3x!=2
x!=2/3
x!=2/3
x∈R
(2x+1)/(3x-2)-(+5/4)=0
We get rid of parentheses
(2x+1)/(3x-2)-5/4=0
We calculate fractions
(8x+4)/(12x-8)+(-15x+10)/(12x-8)=0
We multiply all the terms by the denominator
(8x+4)+(-15x+10)=0
We get rid of parentheses
8x-15x+4+10=0
We add all the numbers together, and all the variables
-7x+14=0
We move all terms containing x to the left, all other terms to the right
-7x=-14
x=-14/-7
x=+2
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