(2x+1)/(3x-4)+(5/7)=1

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Solution for (2x+1)/(3x-4)+(5/7)=1 equation: 


D( x )

3*x-4 = 0

3*x-4 = 0

3*x-4 = 0

3*x-4 = 0 // + 4

3*x = 4 // : 3

x = 4/3

x in (-oo:4/3) U (4/3:+oo)

(2*x+1)/(3*x-4)+5/7 = 1 // - 1

(2*x+1)/(3*x-4)+5/7-1 = 0

(7*(2*x+1))/(7*(3*x-4))+(5*(3*x-4))/(7*(3*x-4))+(-1*7*(3*x-4))/(7*(3*x-4)) = 0

7*(2*x+1)+5*(3*x-4)-1*7*(3*x-4) = 0

29*x-21*x-13+28 = 0

8*x+15 = 0

(8*x+15)/(7*(3*x-4)) = 0

(8*x+15)/(7*(3*x-4)) = 0 // * 7*(3*x-4)

8*x+15 = 0

8*x+15 = 0 // - 15

8*x = -15 // : 8

x = -15/8

x = -15/8

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