(2x+1)/(3x-4)=1/8

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Solution for (2x+1)/(3x-4)=1/8 equation: 


D( x )

3*x-4 = 0

3*x-4 = 0

3*x-4 = 0

3*x-4 = 0 // + 4

3*x = 4 // : 3

x = 4/3

x in (-oo:4/3) U (4/3:+oo)

(2*x+1)/(3*x-4) = 1/8 // - 1/8

(2*x+1)/(3*x-4)-(1/8) = 0

(2*x+1)/(3*x-4)-1/8 = 0

(8*(2*x+1))/(8*(3*x-4))+(-1*(3*x-4))/(8*(3*x-4)) = 0

8*(2*x+1)-1*(3*x-4) = 0

13*x+12 = 0

(13*x+12)/(8*(3*x-4)) = 0

(13*x+12)/(8*(3*x-4)) = 0 // * 8*(3*x-4)

13*x+12 = 0

13*x+12 = 0 // - 12

13*x = -12 // : 13

x = -12/13

x = -12/13

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