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(2x+1)/(3x-7)=3/5
We move all terms to the left:
(2x+1)/(3x-7)-(3/5)=0
Domain of the equation: (3x-7)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
3x!=7
x!=7/3
x!=2+1/3
x∈R
(2x+1)/(3x-7)-(+3/5)=0
We get rid of parentheses
(2x+1)/(3x-7)-3/5=0
We calculate fractions
(10x+5)/(15x-35)+(-9x+21)/(15x-35)=0
We multiply all the terms by the denominator
(10x+5)+(-9x+21)=0
We get rid of parentheses
10x-9x+5+21=0
We add all the numbers together, and all the variables
x+26=0
We move all terms containing x to the left, all other terms to the right
x=-26
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