(2x+1)/(4x-3)=3/4

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Solution for (2x+1)/(4x-3)=3/4 equation: 


D( x )

4*x-3 = 0

4*x-3 = 0

4*x-3 = 0

4*x-3 = 0 // + 3

4*x = 3 // : 4

x = 3/4

x in (-oo:3/4) U (3/4:+oo)

(2*x+1)/(4*x-3) = 3/4 // - 3/4

(2*x+1)/(4*x-3)-(3/4) = 0

(2*x+1)/(4*x-3)-3/4 = 0

(4*(2*x+1))/(4*(4*x-3))+(-3*(4*x-3))/(4*(4*x-3)) = 0

4*(2*x+1)-3*(4*x-3) = 0

13-4*x = 0

(13-4*x)/(4*(4*x-3)) = 0

(13-4*x)/(4*(4*x-3)) = 0 // * 4*(4*x-3)

13-4*x = 0

13-4*x = 0 // - 13

-4*x = -13 // : -4

x = -13/(-4)

x = 13/4

x = 13/4

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