(2x+1)/(x+2)+(x-2)/(x+4)=0

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Solution for (2x+1)/(x+2)+(x-2)/(x+4)=0 equation: 



(2x+1)/(x+2)+(x-2)/(x+4)=0



Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R





Domain of the equation: (x+4)!=0

We move all terms containing x to the left, all other terms to the right

x!=-4

x∈R



We calculate fractions


((2x+1)*(x+4))/((x+2)*(x+4))+((x-2)*(x+2))/((x+2)*(x+4))=0



We calculate terms in parentheses: +((2x+1)*(x+4))/((x+2)*(x+4)), so:

(2x+1)*(x+4))/((x+2)*(x+4)

We multiply all the terms by the denominator


(2x+1)*(x+4))

Back to the equation:

+((2x+1)*(x+4)))





We calculate terms in parentheses: +((x-2)*(x+2))/((x+2)*(x+4)), so:

(x-2)*(x+2))/((x+2)*(x+4)

We multiply all the terms by the denominator


(x-2)*(x+2))

Back to the equation:

+((x-2)*(x+2)))





We calculate terms in parentheses: +((2x+1)*(x+4)))+((x-2)*(x+2))), so:

(2x+1)*(x+4)))+((x-2)*(x+2))

We add all the numbers together, and all the variables

(2x+1)*(x+4)))+((x-2)*(x

Back to the equation:

+((2x+1)*(x+4)))+((x-2)*(x)

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