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(2x+1)/(x+2)=x-1
We move all terms to the left:
(2x+1)/(x+2)-(x-1)=0
Domain of the equation: (x+2)!=0We get rid of parentheses
We move all terms containing x to the left, all other terms to the right
x!=-2
x∈R
(2x+1)/(x+2)-x+1=0
We multiply all the terms by the denominator
(2x+1)-x*(x+2)+1*(x+2)=0
We multiply parentheses
-x^2+(2x+1)-2x+1*(x+2)=0
We get rid of parentheses
-x^2+2x-2x+1*(x+2)+1=0
We add all the numbers together, and all the variables
-1x^2+1*(x+2)+1=0
We move all terms containing x to the left, all other terms to the right
-1x^2+1*(x+2)=-1
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