(2x+1)/(x-3)=(6/7)

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Solution for (2x+1)/(x-3)=(6/7) equation: 


D( x )

x-3 = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:3) U (3:+oo)

(2*x+1)/(x-3) = 6/7 // - 6/7

(2*x+1)/(x-3)-(6/7) = 0

(2*x+1)/(x-3)-6/7 = 0

(7*(2*x+1))/(7*(x-3))+(-6*(x-3))/(7*(x-3)) = 0

7*(2*x+1)-6*(x-3) = 0

8*x+25 = 0

(8*x+25)/(7*(x-3)) = 0

(8*x+25)/(7*(x-3)) = 0 // * 7*(x-3)

8*x+25 = 0

8*x+25 = 0 // - 25

8*x = -25 // : 8

x = -25/8

x = -25/8

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