(2x+1)/2=(x+2)/5

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Solution for (2x+1)/2=(x+2)/5 equation: 


x in (-oo:+oo)

(2*x+1)/2 = (x+2)/5 // - (x+2)/5

(2*x+1)/2-((x+2)/5) = 0

(2*x+1)/2+(-1*(x+2))/5 = 0

(5*(2*x+1))/(2*5)+(-1*2*(x+2))/(2*5) = 0

5*(2*x+1)-1*2*(x+2) = 0

8*x+1 = 0

(8*x+1)/(2*5) = 0

(8*x+1)/(2*5) = 0 // * 2*5

8*x+1 = 0

8*x+1 = 0 // - 1

8*x = -1 // : 8

x = -1/8

x = -1/8

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