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(2x+1)/3+3x=3
We move all terms to the left:
(2x+1)/3+3x-(3)=0
We add all the numbers together, and all the variables
3x+(2x+1)/3-3=0
We multiply all the terms by the denominator
3x*3+(2x+1)-3*3=0
We add all the numbers together, and all the variables
3x*3+(2x+1)-9=0
Wy multiply elements
9x+(2x+1)-9=0
We get rid of parentheses
9x+2x+1-9=0
We add all the numbers together, and all the variables
11x-8=0
We move all terms containing x to the left, all other terms to the right
11x=8
x=8/11
x=8/11
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