(2x+1)/3=(x+6)/2

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Solution for (2x+1)/3=(x+6)/2 equation: 


x in (-oo:+oo)

(2*x+1)/3 = (x+6)/2 // - (x+6)/2

(2*x+1)/3-((x+6)/2) = 0

(2*x+1)/3+(-1*(x+6))/2 = 0

(2*(2*x+1))/(2*3)+(-1*3*(x+6))/(2*3) = 0

2*(2*x+1)-1*3*(x+6) = 0

x-16 = 0

(x-16)/(2*3) = 0

(x-16)/(2*3) = 0 // * 2*3

x-16 = 0

x-16 = 0 // + 16

x = 16

x = 16

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