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(2x+1)/3=3x-16
We move all terms to the left:
(2x+1)/3-(3x-16)=0
We get rid of parentheses
(2x+1)/3-3x+16=0
We multiply all the terms by the denominator
(2x+1)-3x*3+16*3=0
We add all the numbers together, and all the variables
(2x+1)-3x*3+48=0
Wy multiply elements
(2x+1)-9x+48=0
We get rid of parentheses
2x-9x+1+48=0
We add all the numbers together, and all the variables
-7x+49=0
We move all terms containing x to the left, all other terms to the right
-7x=-49
x=-49/-7
x=+7
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