(2x+1)/4=(x-2)/3

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Solution for (2x+1)/4=(x-2)/3 equation: 



(2x+1)/4=(x-2)/3

We move all terms to the left:

(2x+1)/4-((x-2)/3)=0

We calculate fractions


2x/()+(-((x-2)*4)/()=0



We calculate terms in parentheses: +(-((x-2)*4)/(), so:

-((x-2)*4)/(

We multiply all the terms by the denominator


-((x-2)*4)



We calculate terms in parentheses: -((x-2)*4), so:

(x-2)*4

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We get rid of parentheses

-4x+8

Back to the equation:

+(-4x+8)



We get rid of parentheses

2x/()-4x+8=0

We multiply all the terms by the denominator


2x-4x*()+8*()=0

We add all the numbers together, and all the variables

2x-4x*()=0

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