(2x+1)/5=(3x+4)/6

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Solution for (2x+1)/5=(3x+4)/6 equation: 



(2x+1)/5=(3x+4)/6

We move all terms to the left:

(2x+1)/5-((3x+4)/6)=0

We calculate fractions


2x/()+(-((3x+4)*5)/()=0



We calculate terms in parentheses: +(-((3x+4)*5)/(), so:

-((3x+4)*5)/(

We multiply all the terms by the denominator


-((3x+4)*5)



We calculate terms in parentheses: -((3x+4)*5), so:

(3x+4)*5

We multiply parentheses

15x+20

Back to the equation:

-(15x+20)



We get rid of parentheses

-15x-20

Back to the equation:

+(-15x-20)



We get rid of parentheses

2x/()-15x-20=0

We multiply all the terms by the denominator


2x-15x*()-20*()=0

We add all the numbers together, and all the variables

2x-15x*()=0

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