(2x+1)/5=(x-4)/2

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Solution for (2x+1)/5=(x-4)/2 equation: 


x in (-oo:+oo)

(2*x+1)/5 = (x-4)/2 // - (x-4)/2

(2*x+1)/5-((x-4)/2) = 0

(2*x+1)/5+(-1*(x-4))/2 = 0

(2*(2*x+1))/(2*5)+(-1*5*(x-4))/(2*5) = 0

2*(2*x+1)-1*5*(x-4) = 0

22-x = 0

(22-x)/(2*5) = 0

(22-x)/(2*5) = 0 // * 2*5

22-x = 0

22-x = 0 // - 22

-x = -22 // * -1

x = 22

x = 22

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