(2x+1)/7-(3x+2)/14=x

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Solution for (2x+1)/7-(3x+2)/14=x equation: 


x in (-oo:+oo)

(2*x+1)/7-((3*x+2)/14) = x // - x

(2*x+1)/7-((3*x+2)/14)-x = 0

(2*x+1)/7+(-1*(3*x+2))/14-x = 0

(14*(2*x+1))/(7*14)+(-1*7*(3*x+2))/(7*14)+(7*14*(-x))/(7*14) = 0

14*(2*x+1)-1*7*(3*x+2)+7*14*(-x) = 0

7*x-98*x = 0

-91*x = 0

(-91*x)/(7*14) = 0

(-91*x)/(7*14) = 0 // * 7*14

-91*x = 0

-91*x = 0 // : -91

x = 0

x = 0

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