(2x+1)/9=(1-x)/6

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Solution for (2x+1)/9=(1-x)/6 equation: 



(2x+1)/9=(1-x)/6

We move all terms to the left:

(2x+1)/9-((1-x)/6)=0

We add all the numbers together, and all the variables

(2x+1)/9-((-1x+1)/6)=0

We calculate fractions


2x/()+(-((-1x+1)*9)/()=0



We calculate terms in parentheses: +(-((-1x+1)*9)/(), so:

-((-1x+1)*9)/(

We multiply all the terms by the denominator


-((-1x+1)*9)



We calculate terms in parentheses: -((-1x+1)*9), so:

(-1x+1)*9

We multiply parentheses

-9x+9

Back to the equation:

-(-9x+9)



We get rid of parentheses

9x-9

Back to the equation:

+(9x-9)



We get rid of parentheses

2x/()+9x-9=0

We multiply all the terms by the denominator


2x+9x*()-9*()=0

We add all the numbers together, and all the variables

2x+9x*()=0

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