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((2*x+1)^1)/3 = 5 // - 5
((2*x+1)^1)/3-5 = 0
(2*x+1)/3-5 = 0
(2*x+1)/3+(-5*3)/3 = 0
2*x-5*3+1 = 0
2*x-14 = 0
(2*x-14)/3 = 0
(2*x-14)/3 = 0 // * 3
2*x-14 = 0
2*x-14 = 0 // + 14
2*x = 14 // : 2
x = 14/2
x = 7
x = 7
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