(2x+1)=(8x-2)

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Solution for (2x+1)=(8x-2) equation: 



(2x+1)=(8x-2)

We move all terms to the left:

(2x+1)-((8x-2))=0

We get rid of parentheses

2x-((8x-2))+1=0



We calculate terms in parentheses: -((8x-2)), so:

(8x-2)

We get rid of parentheses

8x-2

Back to the equation:

-(8x-2)



We get rid of parentheses

2x-8x+2+1=0

We add all the numbers together, and all the variables

-6x+3=0

We move all terms containing x to the left, all other terms to the right

-6x=-3

x=-3/-6

x=1/2

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