(2x+1)=27+(6x-15)

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Solution for (2x+1)=27+(6x-15) equation: 



(2x+1)=27+(6x-15)

We move all terms to the left:

(2x+1)-(27+(6x-15))=0

We get rid of parentheses

2x-(27+(6x-15))+1=0



We calculate terms in parentheses: -(27+(6x-15)), so:

27+(6x-15)

determiningTheFunctionDomain
(6x-15)+27

We get rid of parentheses

6x-15+27

We add all the numbers together, and all the variables

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

2x-6x-12+1=0

We add all the numbers together, and all the variables

-4x-11=0

We move all terms containing x to the left, all other terms to the right

-4x=11

x=11/-4

x=-2+3/4

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