(2x+1)=29+3(2x-5)

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Solution for (2x+1)=29+3(2x-5) equation: 



(2x+1)=29+3(2x-5)

We move all terms to the left:

(2x+1)-(29+3(2x-5))=0

We get rid of parentheses

2x-(29+3(2x-5))+1=0



We calculate terms in parentheses: -(29+3(2x-5)), so:

29+3(2x-5)

determiningTheFunctionDomain
3(2x-5)+29

We multiply parentheses

6x-15+29

We add all the numbers together, and all the variables

6x+14

Back to the equation:

-(6x+14)



We get rid of parentheses

2x-6x-14+1=0

We add all the numbers together, and all the variables

-4x-13=0

We move all terms containing x to the left, all other terms to the right

-4x=13

x=13/-4

x=-3+1/4

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