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(2x+1)=4(x-1)+x-1
We move all terms to the left:
(2x+1)-(4(x-1)+x-1)=0
We get rid of parentheses
2x-(4(x-1)+x-1)+1=0
We calculate terms in parentheses: -(4(x-1)+x-1), so:We get rid of parentheses
4(x-1)+x-1
We add all the numbers together, and all the variables
x+4(x-1)-1
We multiply parentheses
x+4x-4-1
We add all the numbers together, and all the variables
5x-5
Back to the equation:
-(5x-5)
2x-5x+5+1=0
We add all the numbers together, and all the variables
-3x+6=0
We move all terms containing x to the left, all other terms to the right
-3x=-6
x=-6/-3
x=+2
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