(2x+1)=4(x-1)+x-1

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Solution for (2x+1)=4(x-1)+x-1 equation: 



(2x+1)=4(x-1)+x-1

We move all terms to the left:

(2x+1)-(4(x-1)+x-1)=0

We get rid of parentheses

2x-(4(x-1)+x-1)+1=0



We calculate terms in parentheses: -(4(x-1)+x-1), so:

4(x-1)+x-1

We add all the numbers together, and all the variables

x+4(x-1)-1

We multiply parentheses

x+4x-4-1

We add all the numbers together, and all the variables

5x-5

Back to the equation:

-(5x-5)



We get rid of parentheses

2x-5x+5+1=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2

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