(2x+1)x+5=2

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Solution for (2x+1)x+5=2 equation:


Simplifying
(2x + 1) * x + 5 = 2

Reorder the terms:
(1 + 2x) * x + 5 = 2

Reorder the terms for easier multiplication:
x(1 + 2x) + 5 = 2
(1 * x + 2x * x) + 5 = 2
(1x + 2x2) + 5 = 2

Reorder the terms:
5 + 1x + 2x2 = 2

Solving
5 + 1x + 2x2 = 2

Solving for variable 'x'.

Reorder the terms:
5 + -2 + 1x + 2x2 = 2 + -2

Combine like terms: 5 + -2 = 3
3 + 1x + 2x2 = 2 + -2

Combine like terms: 2 + -2 = 0
3 + 1x + 2x2 = 0

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
1.5 + 0.5x + x2 = 0

Move the constant term to the right:

Add '-1.5' to each side of the equation.
1.5 + 0.5x + -1.5 + x2 = 0 + -1.5

Reorder the terms:
1.5 + -1.5 + 0.5x + x2 = 0 + -1.5

Combine like terms: 1.5 + -1.5 = 0.0
0.0 + 0.5x + x2 = 0 + -1.5
0.5x + x2 = 0 + -1.5

Combine like terms: 0 + -1.5 = -1.5
0.5x + x2 = -1.5

The x term is 0.5x.  Take half its coefficient (0.25).
Square it (0.0625) and add it to both sides.

Add '0.0625' to each side of the equation.
0.5x + 0.0625 + x2 = -1.5 + 0.0625

Reorder the terms:
0.0625 + 0.5x + x2 = -1.5 + 0.0625

Combine like terms: -1.5 + 0.0625 = -1.4375
0.0625 + 0.5x + x2 = -1.4375

Factor a perfect square on the left side:
(x + 0.25)(x + 0.25) = -1.4375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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