(2x+1)x-1/2=0

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Solution for (2x+1)x-1/2=0 equation: 


x in (-oo:+oo)

x*(2*x+1)-(1/2) = 0

x*(2*x+1)-1/2 = 0

(2*x*(2*x+1))/2-1/2 = 0

2*x*(2*x+1)-1 = 0

4*x^2+2*x-1 = 0

4*x^2+2*x-1 = 0

4*x^2+2*x-1 = 0

DELTA = 2^2-(-1*4*4)

DELTA = 20

DELTA > 0

x = (20^(1/2)-2)/(2*4) or x = (-20^(1/2)-2)/(2*4)

x = (2*5^(1/2)-2)/8 or x = (-2*5^(1/2)-2)/8

(x-((-2*5^(1/2)-2)/8))*(x-((2*5^(1/2)-2)/8)) = 0

((x-((-2*5^(1/2)-2)/8))*(x-((2*5^(1/2)-2)/8)))/2 = 0

((x-((-2*5^(1/2)-2)/8))*(x-((2*5^(1/2)-2)/8)))/2 = 0 // * 2

(x-((-2*5^(1/2)-2)/8))*(x-((2*5^(1/2)-2)/8)) = 0

( x-((-2*5^(1/2)-2)/8) )

x-((-2*5^(1/2)-2)/8) = 0 // + (-2*5^(1/2)-2)/8

x = (-2*5^(1/2)-2)/8

( x-((2*5^(1/2)-2)/8) )

x-((2*5^(1/2)-2)/8) = 0 // + (2*5^(1/2)-2)/8

x = (2*5^(1/2)-2)/8

x in { (-2*5^(1/2)-2)/8, (2*5^(1/2)-2)/8 }

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