(2x+1/(x+2))+3=0

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Solution for (2x+1/(x+2))+3=0 equation: 


D( x )

x+2 = 0

x+2 = 0

x+2 = 0

x+2 = 0 // - 2

x = -2

x in (-oo:-2) U (-2:+oo)

1/(x+2)+2*x+3 = 0

1/(x+2)+(2*x*(x+2))/(x+2)+(3*(x+2))/(x+2) = 0

2*x*(x+2)+3*(x+2)+1 = 0

2*x^2+4*x+3*x+1+6 = 0

2*x^2+7*x+7 = 0

2*x^2+7*x+7 = 0

2*x^2+7*x+7 = 0

DELTA = 7^2-(2*4*7)

DELTA = -7

DELTA < 0

1 = 0

1/(x+2) = 0

1/(x+2) = 0 // * x+2

1 = 0

x belongs to the empty set

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