(2x+1/x-3)-(x-3/x+5)=(-10x+14/x+5)

Solution for (2x+1/x-3)-(x-3/x+5)=(-10x+14/x+5) equation:

D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x-x+1/x+3/x-5-3 = 14/x-10*x+5 // - 14/x-10*x+5

2*x-x-(-10*x)+1/x+3/x-(14/x)-5-5-3 = 0

2*x-x+10*x+1/x+3/x-14*x^-1-5-5-3 = 0

11*x^1-10*x^-1-13*x^0 = 0

(11*x^2-13*x^1-10*x^0)/(x^1) = 0 // * x^2

x^1*(11*x^2-13*x^1-10*x^0) = 0

x^1

11*x^2-13*x-10 = 0

11*x^2-13*x-10 = 0

DELTA = (-13)^2-(-10*4*11)

DELTA = 609

DELTA > 0

x = (609^(1/2)+13)/(2*11) or x = (13-609^(1/2))/(2*11)

x = (609^(1/2)+13)/22 or x = (13-609^(1/2))/22

x in { (13-609^(1/2))/22, (609^(1/2)+13)/22} 

x in { (13-609^(1/2))/22, (609^(1/2)+13)/22 }