(2x+10)(2x+20)=600

Solution for (2x+10)(2x+20)=600 equation:

(2x+10)(2x+20)=600

We move all terms to the left:

(2x+10)(2x+20)-(600)=0

We multiply parentheses ..

(+4x^2+40x+20x+200)-600=0

We get rid of parentheses

4x^2+40x+20x+200-600=0

We add all the numbers together, and all the variables

4x^2+60x-400=0

a = 4; b = 60; c = -400;
Δ = b2-4ac
Δ = 602-4·4·(-400)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-100}{2*4}=\frac{-160}{8}
=-20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+100}{2*4}=\frac{40}{8}
=5
$