(2x+10)(2x+5)=150

Solution for (2x+10)(2x+5)=150 equation:

(2x+10)(2x+5)=150

We move all terms to the left:

(2x+10)(2x+5)-(150)=0

We multiply parentheses ..

(+4x^2+10x+20x+50)-150=0

We get rid of parentheses

4x^2+10x+20x+50-150=0

We add all the numbers together, and all the variables

4x^2+30x-100=0

a = 4; b = 30; c = -100;
Δ = b2-4ac
Δ = 302-4·4·(-100)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-50}{2*4}=\frac{-80}{8}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+50}{2*4}=\frac{20}{8}
=2+1/2
$