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(2x+10)(3x-9)=0
We multiply parentheses ..
(+6x^2-18x+30x-90)=0
We get rid of parentheses
6x^2-18x+30x-90=0
We add all the numbers together, and all the variables
6x^2+12x-90=0
a = 6; b = 12; c = -90;
Δ = b2-4ac
Δ = 122-4·6·(-90)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-48}{2*6}=\frac{-60}{12} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+48}{2*6}=\frac{36}{12} =3 $
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