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(2x+10)(4x+2)=90
We move all terms to the left:
(2x+10)(4x+2)-(90)=0
We multiply parentheses ..
(+8x^2+4x+40x+20)-90=0
We get rid of parentheses
8x^2+4x+40x+20-90=0
We add all the numbers together, and all the variables
8x^2+44x-70=0
a = 8; b = 44; c = -70;
Δ = b2-4ac
Δ = 442-4·8·(-70)
Δ = 4176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4176}=\sqrt{144*29}=\sqrt{144}*\sqrt{29}=12\sqrt{29}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-12\sqrt{29}}{2*8}=\frac{-44-12\sqrt{29}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+12\sqrt{29}}{2*8}=\frac{-44+12\sqrt{29}}{16} $
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