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(2x+10)(6x+1)=79
We move all terms to the left:
(2x+10)(6x+1)-(79)=0
We multiply parentheses ..
(+12x^2+2x+60x+10)-79=0
We get rid of parentheses
12x^2+2x+60x+10-79=0
We add all the numbers together, and all the variables
12x^2+62x-69=0
a = 12; b = 62; c = -69;
Δ = b2-4ac
Δ = 622-4·12·(-69)
Δ = 7156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7156}=\sqrt{4*1789}=\sqrt{4}*\sqrt{1789}=2\sqrt{1789}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(62)-2\sqrt{1789}}{2*12}=\frac{-62-2\sqrt{1789}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(62)+2\sqrt{1789}}{2*12}=\frac{-62+2\sqrt{1789}}{24} $
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