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(2x+10)(x+30)=4x+30
We move all terms to the left:
(2x+10)(x+30)-(4x+30)=0
We get rid of parentheses
(2x+10)(x+30)-4x-30=0
We multiply parentheses ..
(+2x^2+60x+10x+300)-4x-30=0
We get rid of parentheses
2x^2+60x+10x-4x+300-30=0
We add all the numbers together, and all the variables
2x^2+66x+270=0
a = 2; b = 66; c = +270;
Δ = b2-4ac
Δ = 662-4·2·270
Δ = 2196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2196}=\sqrt{36*61}=\sqrt{36}*\sqrt{61}=6\sqrt{61}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-6\sqrt{61}}{2*2}=\frac{-66-6\sqrt{61}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+6\sqrt{61}}{2*2}=\frac{-66+6\sqrt{61}}{4} $
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