(2x+10)+(3x-5)=80

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Solution for (2x+10)+(3x-5)=80 equation: 



(2x+10)+(3x-5)=80

We move all terms to the left:

(2x+10)+(3x-5)-(80)=0

We get rid of parentheses

2x+3x+10-5-80=0

We add all the numbers together, and all the variables

5x-75=0

We move all terms containing x to the left, all other terms to the right

5x=75

x=75/5

x=15

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