(2x+10)x=32

Solution for (2x+10)x=32 equation:

(2x+10)x=32

We move all terms to the left:

(2x+10)x-(32)=0

We multiply parentheses

2x^2+10x-32=0

a = 2; b = 10; c = -32;
Δ = b2-4ac
Δ = 102-4·2·(-32)
Δ = 356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{356}=\sqrt{4*89}=\sqrt{4}*\sqrt{89}=2\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{89}}{2*2}=\frac{-10-2\sqrt{89}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{89}}{2*2}=\frac{-10+2\sqrt{89}}{4}
$